A circuit with three 30 Ω resistors in parallel is connected to a 20 V source. The total current drawn is:

A circuit with three 30 Ω resistors in parallel is connected to a 20 V source. The total current drawn is:

• A. 0.5 A
• B. 6 A
• C. 60 A
• D. 2 A

Answer: (D)

Parallel resistors share the same voltage, and their combined (equivalent) resistance is lower than any single resistor. For three 30 Ω resistors in parallel, 1/R_eq = 1/30 + 1/30 + 1/30 = 3/30 = 1/10, so R_eq = 10 Ω. With a 20 V source, the total current drawn is I = V / R_eq = 20 V / 10 Ω = 2 A. Equivalently, each branch carries I_branch = V / R = 20 V / 30 Ω ≈ 0.667 A, and the total current is 3 × 0.667 A ≈ 2 A.

Parallel resistors share the same voltage, and their combined (equivalent) resistance is lower than any single resistor. For three 30 Ω resistors in parallel, 1/R_eq = 1/30 + 1/30 + 1/30 = 3/30 = 1/10, so R_eq = 10 Ω. With a 20 V source, the total current drawn is I = V / R_eq = 20 V / 10 Ω = 2 A.

Equivalently, each branch carries I_branch = V / R = 20 V / 30 Ω ≈ 0.667 A, and the total current is 3 × 0.667 A ≈ 2 A.